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Joat42
Posts: 2164
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So no one here actually understands how a gravity field affect objects entering it?
Especially when the gradient is extremely steep? --- Jack of all trades and destructive tinkerer. Anyone who have simple solutions for complex problems is a fool. |
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tlb
Posts: 4744
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It seems safe to say that there are various opinions. I have given text for the result of a low velocity object entering a focused gravity wall. Based on that, I do not understand why some people believe what they write. |
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ThinksMarkedly
Posts: 4645
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The scientific term for that is "spaghettification." And the phase depths of a neutron star crust are called: gnocchi phase, spaghetti phase, lasagna phase, anti-spaghetti, and anti-gnocchi phase. One can wonder if they shouldn't name things while hungry... |
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Jonathan_S
Posts: 9030
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Seems to be 0.99c for both drones and ships - here's a bit I found in the extended 'In Fury Born'
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tlb
Posts: 4744
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Thank you, that actually puts TV Tropes closer to correct; but it is easy to see why Loren Pechtel's memory was of 0.9c. But does anyone know what the original Path of the Fury said? Was it the same? Spoiler Alert for the Fury series: It turns out that the Mission of Honor CD has both revised Fury stories. But having read the original, I am not sure I want to read the new ones. My problem is that I know the critical point (which is at the beginning of the original). It is when she should not have survived a pirate attack that kills the rest of her family. |
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Loren Pechtel
Posts: 1324
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Sidewalls and wedges are different cases. Wedges seem to be able to stand up to anything other than other wedges. I don't think there's any meaningful attack through them, you can only go around. Sidewalls, however, I do not believe can stop an ultrarelativistic missile. Even if you successfully deflect the matter they're not going to stop the energy. |
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Loren Pechtel
Posts: 1324
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That's my thought, also. I'm simply saying that even if it does deflect the missile that doesn't save what's behind the sidewall--deflecting that matter will cause it to dump it's energy in synchrotron radiation. Gammas are attenuated by the sidewall, not stopped--and one ultrarelativistic missile carries far more energy than every beam from the whole magazine of a podnaught. |
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Loren Pechtel
Posts: 1324
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Yup, that's the bit that came to mind and I'll concede that it's .99c rather than .9c. It still isn't lightspeed and the wormhole isn't simply the Fasset drive. They use the Fasset drive to get up to the speed needed for the wormhole drive. |
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Joat42
Posts: 2164
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You are all confusing acceleration/deacceleration as per Newtonian physics with how gravity affects an object's acceleration/deacceleration from an outside observer's perspective. From an object's internal perspective, being in a high gravity field is exactly the same as being in zero gravity. Synchrotron radiation only occurs when a fast traveling charged particle is subjected to strong magnetic or electric fields - see Larmor's formula. A particle only affected by strong gravitational fields does not produce synchrotron radiation, it only changes it's speed and direction. An object passing through a high gradient gravity field will be ripped apart, if the gradient is steep enough you will get secondary effects due to internal friction when atoms accelerates faster than its surrounding companions plus you have atomic bonds being broken which also tend to release energy. At no point does this release the latent kinetic energy of the object. If it did, any object passing through a gravitational field must give up it's latent kinetic energy in some fashion - like for example it gets hotter or it starts emitting spurious radiation, which would essentially make spaceships an impossible proposition. --- Jack of all trades and destructive tinkerer. Anyone who have simple solutions for complex problems is a fool. |
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tlb
Posts: 4744
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The Honorverse might not work exactly the way that books say our universe works. I have given you the text for an event with low kinetic energy. As seen the object was ripped apart, just as you say can happen. So once the object has been reduced to a plasma, where exactly is the input kinetic energy supposed to reside? Isn't it spread though the atoms of that plasma, making everything even more energetic? The object stopped at the wall and then it and all its incoming energy was transformed into an energetic gas cloud propagating outward and radiating light and heat. This has nothing to do with an object passing through the normal gravitational field of a star or planet, because those are not specifically designed to be destructive for the object. This is for fields created to stop the object and reduce it to plasma. You have been writing as though the remains of the object should go off in some preferred direction; but that will only happen if momentum is in some measure preserved. Perhaps it would be if the bullet had hit at a glancing angle, but when it comes in at close to perpendicular to the wall, then no momentum survives. |
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