tlb wrote:tlb wrote:To be fair, the SLN missiles were in a ballistic phase when any wedge could have destroyed them and the salvo of missiles were aimed at the SLN ships, so the RMN accomplished a two for the price of one piece of economy.kzt wrote:Except the geometry doesn't work. It's another magic solution.
Please explain how the geometry does not work. Naively I would expect that the track for a missile going from the SLN to the RMN ship, could also be used as the track of a missile going from the RMN to the SLN ship. By using the reciprocal course the RMN missile wedge kills the SLN missile, since the RMN missile can be powered the entire distance (unlike that of the SLN).
So missiles without special guidance by an insane tactical team need to be oriented such that each missile nose (which has the sensors) is pointed at the target and the the tail (which has the guidance transmitters and receivers) needs to be pointed vaguely at the launching vessel.
In addition the missiles need to be at least 20km apart as they have a 10km diameter wedge.
So to do this the default arrangement of the missiles will be a flat plane perpendicular to the target.
I don’t have the burn-out velocity handy, but it’s moving at a something over 25,000 km sec.
To engage more than one missile you have to approach the flat plane from the sides. Now the first question is “how do you do this, given that the mk23s seems launched from generally in front?”
Assuming you can do this, the next question is “how long will the mk23s be in the 10km wide path through the formation?” We’ll assume they are moving laterally at the same 25,000 km/sec velocity and with zero velocity towards the SLN ships. So at 25,000km sec velocity across the formation they have 1/2500 of a second. During which the Mk23 will move 10km across the formation.
So each Mk23 can kill exactly one missile.