Relax wrote:1) Solve in reverse. Time to get a CM to minimal interception range from the ship. Assume the firing key has already been depressed and its in the tube ready to go via C&C loop etc.
What is its initial Velocity? 1000km/s via mass driver?
Go with a wedge depth from ship of 50KM or so(small ship)
If 1000km/s v0 then requires essentially no time just to clear the ships wedge. t ~ 0.05
Lets go with ~0s for best scenario.
What is minimal distance before you do NOT fire and rather use PDLC? 100,000km?
Assume best scenario: v0 = 1k km/s, a = 10kmpss
t = time to clear wedge(0s) and get to 100k km = 13s
Distance at which you need to determine if one "blob" = two missiles. Assuming you do not know how many missiles were fired to begin with... which the books all say is rather apparent so we are left to believe a computer all of a sudden can't count to 20 without taking its socks off... and likewise can't put CM's in line with each other... Now add reaction time of a human who has to select the missed missile and hit fire instead of the computer doing it... As if the computer doesn't already know Friend from Foe Missiles aren't exactly stealthy you know...
V incoming, Best case scenario, SDM, 13s @100,000km intercept, is 1,000,000km @0.25c for distinguishing between 1 and 2 missiles. Assuming you have spare CM's that were not already launched for some odd reason... Its not like you don't already know that CM's miss incoming targets...
This is the equivalent of saying a human in a wet navy today should be in charge of using the CIWS/SEARAM... You might have noticed but no navy on earth is that stupid...
I'm not sure a CM has to coast clear of the ship's wedge before lighting off. It has to get over 5 km past the sidewalls - so over 15 km from the ship's hull. But as long as you don't clip the ship's wedge with your missile's wedge you can have one wedge active inside another -- otherwise they wouldn't have needed to invent sidewalls to protect ships against wedge contact missiles (as described in the armor essay from IFF)
Though since the CM's wedge is wider than the ship you can obviously can't have 2 light off simultaneously from the same broadside...
But that might let you cut down on the lag time to coast clear of the wedge that you had built into your calculations.